Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.5 - Linear Programming - Exercise Set - Page 305: 37


The answer is $f(-1)=10$.

Work Step by Step

The given function is $f(x)=x^3+2x^2-5x+4$ Plug $x=-1$ into the function. $f(-1)=(-1)^3+2(-1)^2-5(-1)+4$ Simplify. $f(-1)=-1+2+5+4$ $f(-1)=10$.
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