## Intermediate Algebra for College Students (7th Edition)

The answer is $54 x^{7}y^{15}$.
The given expression is $(2x^4y^3)(3xy^4)^3$ Multiply the power of the bracket with power of terms inside the bracket. $(2x^4y^3)(3^3x^3y^{12})$ Clear the parentheses and add powers of the like terms. $2\cdot3^3\cdot x^{4+3}y^{3+12}$ Simplify. $54 x^{7}y^{15}$.