Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.5 - Linear Programming - Exercise Set - Page 305: 35


The answer is $54 x^{7}y^{15}$.

Work Step by Step

The given expression is $(2x^4y^3)(3xy^4)^3$ Multiply the power of the bracket with power of terms inside the bracket. $(2x^4y^3)(3^3x^3y^{12})$ Clear the parentheses and add powers of the like terms. $2\cdot3^3\cdot x^{4+3}y^{3+12}$ Simplify. $54 x^{7}y^{15}$.
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