Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.5 - Linear Programming - Exercise Set - Page 305: 36

Answer

The answer is $L=\frac{12P+W}{2}$.

Work Step by Step

The given expression is $ 3P=\frac{2L-W}{4} $ Multiply both sides by $4$. $4\cdot 3P= 4\cdot \left (\frac{2L-W}{4} \right )$ Simplify. $12P=2L-W$ Add $W$ to both sides. $12P+W=2L-W+W$ Simplify. $12P+W=2L$ Divide both sides by $2$. $\frac{12P+W}{2}=\frac{2L}{2}$ Simplify. $\frac{12P+W}{2}=L$ Rearrange. $L=\frac{12P+W}{2}$.
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