Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 284: 86


$\dfrac{-(b+c)}{a}\leq x \leq \dfrac{c-b}{a}$

Work Step by Step

Given: $|ax+b| \geq c$ As per definition of absolute value, we can write this as: or, $-c \geq ax+b \geq c$ or,$-c-b \geq ax \geq c-b$ This implies that: $\dfrac{-(b+c)}{a}\geq x \geq \dfrac{c-b}{a}$ Hence, $\dfrac{-(b+c)}{a}\leq x \leq \dfrac{c-b}{a}$
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