Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 284: 78



Work Step by Step

Given: $|3x+1|=|6x-2|$ or,$3x+1=6x-2$ and $3x+1=-(6x-2)$ or, $3x-6x=-2-1$ and $3x+1=-6x+2$ or, $-3x=-3$ and $3x+6x=2-1$ or, $x=1$ and $x=\dfrac{1}{9}$ Hence, {$\dfrac{1}{9},1$}
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