Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 284: 57

Answer

$(-6,0)$. The graph is shown below.

Work Step by Step

The given expression is $\Rightarrow \left | \frac{2x+6}{3}\right |\lt2$ Rewrite the inequality without absolute value bars. $\Rightarrow -2\lt \frac{2x+6}{3}\lt2$ Solve compound inequality. Multiply all three parts by $3$. $\Rightarrow -2(3)\lt \frac{2x+6}{3}(3)\lt2(3)$ Simplify. $\Rightarrow -6\lt 2x+6\lt6$ Add $-6$ to all three parts. $\Rightarrow -6-6\lt 2x+6-6\lt6-6$ Simplify. $\Rightarrow -12\lt 2x\lt0$ Divide by $2$ to all three parts. $\Rightarrow \frac{-12}{2}\lt \frac{2x}{2}\lt\frac{0}{2}$ Simplify. $\Rightarrow -6\lt x\lt0$ The solution set $(-6,0)$.
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