Intermediate Algebra for College Students (7th Edition)

Published by Pearson

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 208: 76

Answer

The equation is $16a+4b+c=1682$.

Work Step by Step

The given equation is $y=ax^2+bx+c$ ... (1). Substitute $x=4$ and $y=1682$ into the equation (1). $1682=a(4)^2+b(4)+c$ Clear parentheses. $1682 = 16a+4b+c$ Rearrange. $16a+4b+c=1682$.

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