Answer
Point-slope form $ y-0=1(x+3)$.
Slope-intercept form $y=x+3$.
Work Step by Step
The given parallel line equation is
$\Rightarrow -x+y=7$
Isolate $y$.
$\Rightarrow y=x+7$
This is the slope intercept form $y=mx+c$.
Where, slope $m=1$.
Two parallel lines have same slope.
Hence, the slope of the required line is $m=1$.
The given point is $(x_1,y_1)=(-3,0)$.
The point-slope form is
$\Rightarrow y-y_1=m(x-x_1)$
Plug all values.
$\Rightarrow y-0=1(x-(-3))$
Simplify.
$\Rightarrow y-0=1(x+3)$
Isolate $y$ in the above equation.
$\Rightarrow y=1(x+3)$
Apply distributive property.
$\Rightarrow y=x+3$
The above equation is the slope-intercept form.
