Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 208: 67

Answer

$x=8,y=4$

Work Step by Step

As per the given statement we can see that $6x+y=52$ and $x+4y=24$ Here x=number of hexagonal shapes and y= number of squares After plugging $x=24-2y$ from the first equation in the second equation, we have $-23y=-92$ or, $y=4$ Now, $6x+4=52$ or, $6x=48 \implies x= 8$ Thus, $x=8,y=4$
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