## Intermediate Algebra for College Students (7th Edition)

$x=500, P(x)=140x-70000$
Given: $C(x)=105x+70000$ and $R(x)=245x$ After equating the given two equation, we get $140x=70000$ or, $x=500$ Now, $P(x)=245x-(105x+70000)$ or, $P(x)=140x-70000$ Thus, $x=500, P(x)=140x-70000$