Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 204: 3

Answer

$x=2,y=5$

Work Step by Step

Given: $3x-y=1$ and $x+2y=12$ After subtracting the first equation by thrice times of the second equations, we get $-7y=-35$ or, $y=5$ Now, $x+2(5)=12$ or, $x=12-10=2$ Thus, $x=2,y=5$
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