## Intermediate Algebra for College Students (7th Edition)

$x=2,y=1$
Given: $3x+2y=8$ and $2x-y=3$ After adding the first equation by two times of the second equations, we get $7x=14$ or, $x=2$ Now, $3(2)+2y=8$ or, $2y=8-6$ Thus, $x=2,y=1$