Answer
(a.) Slope-intercept form $y=\frac{-1}{4}x+8$.
Slope is $m=\frac{-1}{4}$.
(b.) The slope of the second line is $ 4 $.
Work Step by Step
(a) The standard slope-intercept form is $y=mx+c$.
Where, $m=$ slope and $c=y−$intercept.
The given equation is $x+4y-8=0$.
Isolate $y$.
$y=\frac{-1}{4}x+8$.
The slope of the equation is $m=\frac{-1}{4}$.
(b.) Let the second line's slope is $ m_1 $.
From question.
$ m \times m_1 =-1 $
Substitute values.
$ \frac{-1}{4}\times m_1 =-1 $
Isolate $ m_1 $.
$ m_1 = 4 $.
