Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.4 - Linear Functions and Slope - Exercise Set - Page 155: 118

Answer

Hence, the coefficient are $ 1,-2 $.

Work Step by Step

Let the coefficients are $ a $ and $ b $. Therefore, the equation will be. $ ax+by=12 $ ... (1) The standard $ y- $intercept form is $ y=mx+c $ Isolate $ y $ in the equation (1). $ y= \frac{-a}{b}x+\frac{12}{b} $ Where, $ y- $ intercept is $ \frac{12}{b} $. In the question we have $ y- $ intercept $ -6 $ equate both. $ -6 =\frac{12}{b} $ $ -6b=12 $ $ b=\frac{12}{-6} $ $ b=-2 $ And the slope is $\frac{-a}{b}$. In the question we have $ \frac{1}{2} $ equate both. $ \frac{-a}{b} = \frac{1}{2} $ Substitute the value of $ b $. $ \frac{-a}{-2} = \frac{1}{2} $ $ \frac{a}{2} = \frac{1}{2} $ $ a=1 $.
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