Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.4 - Linear Functions and Slope - Exercise Set - Page 155: 120

Answer

$16x^4y^6$

Work Step by Step

$(\frac{4x^2}{y^{-3}})^2=\frac{(4x^2)^2}{(y^{-3})^2}=\frac{16x^4}{y^-6}=16x^4y^6$
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