Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set - Page 840: 45

Answer

First three terms: $8,13,18$ last term: $88$ Sum of the an arithmetic series: $816$

Work Step by Step

First three terms can be found as:$a_1=5+3=8;a_2=10+13=13;a_3=15+3=18$ Last term can be found as: $a_{17}=5(17)+3=88$ Sum of the an arithmetic series can be calculated by using formula $S_n=\dfrac{n}{2}(a_1+a_n)$ Here $n=17$ Thus, $S_{12}=\dfrac{17}{2}(8+88)=816$ our results are: First three terms: $8,13,18$ last term: $88$ Sum of the an arithmetic series: $816$
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