Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set - Page 839: 44

Answer

$504$

Work Step by Step

Sum of the an arithmetic series can be calculated by using formula $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$ Since, from $31$ to $53$ , we have $(\dfrac{53-31}{2})+1=11+1=12$ Here $n=12$ Thus, $S_{12}=\dfrac{12}{2}(2(31)+11(2))=504$
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