Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 767: 99

Answer

$$\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1$$

Work Step by Step

$$25x^{2} + 16y^{2} = 400$$ Divide both sides by $400$. $$\frac{25x^{2} + 16y^{2}}{400} = \frac{400}{400}$$ $$\frac{25x^{2}}{400} + \frac{16y^{2}}{400} = 1$$ Simplify: $$\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1$$
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