Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 767: 96


$-\frac{5}{2}\lt x\lt\frac{15}{2}$

Work Step by Step

$|x|\lt a$ implies $-a\lt x\lt a$, hence here: $|2x-5|\lt10\\-10\lt2x-5\lt10\\-5\lt2x\lt15\\-\frac{5}{2}\lt x\lt\frac{15}{2}$
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