Answer
$-\frac{5}{2}\lt x\lt\frac{15}{2}$
Work Step by Step
$|x|\lt a$ implies $-a\lt x\lt a$, hence here: $|2x-5|\lt10\\-10\lt2x-5\lt10\\-5\lt2x\lt15\\-\frac{5}{2}\lt x\lt\frac{15}{2}$
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