Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 767: 86

Answer

See below.

Work Step by Step

The center of the given equation is $(3,-5)$ and not $(-3,5)$ because the center of the circle with the equation $(x-k)^2+(y-h)^2=r^2$ is $(k,h)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.