Answer
$x=${$2,3$}
Work Step by Step
Since, we have found that LCD $=(x+3)(x-3)$
Thus, $5(x+3)=1(x+3)(x-3)+30$
or, $5x+15=(x^2-3^2)+30$
or, $5x+15=x^2-9+30$
or, $x^2-5x+6=0$
or, $(x-3)(x-2)=0$
Hence, solution set: $x=${$2,3$}
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 10 - Cumulative Review Exercises - Page 818: 3
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