Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Cumulative Review Exercises - Page 818: 14

Answer

The answer is $2xy^2\sqrt[3] {2y}$.

Work Step by Step

The given expression is $\sqrt[3] {4x^2y^5}\cdot \sqrt[3] {4xy^2}$ By using power rule {$a^n\cdot b^n = (a\cdot b)^n$} $\sqrt[3] {4x^2y^5 \cdot 4xy^2}$ Add powers of the like terms. $\sqrt[3] {16x^3y^7}$ Rearrange. $\sqrt[3] {2^3\cdot 2x^3y^6\cdot y}$ Simplify. $2xy^2\sqrt[3] {2y}$.
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