Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Cumulative Review Exercises - Page 818: 12

Answer

$46$

Work Step by Step

$-2(3^2-12)^3-45\div9-3=-2(9-12)^3-5-3=-2(-3)^3-8=-2(-27)-8=54-8=46$
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