Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Test - Page 102: 40

Answer

$$\frac{4 \times10^{-3}}{8 \times 10^{-7}} = 5\times 10^{3}$$

Work Step by Step

$$\frac{4 \times10^{-3}}{8 \times 10^{-7}}$$ Recall the division of numbers in scientific notation: $\frac{a \times 10^{n}}{b \times 10^{m}} = (\frac{a}{b}) \times 10^{n-m}$ Thus, $$\frac{4 \times10^{-3}}{8 \times 10^{-7}} = \frac{4}{8} \times 10^{-3-(-7)}$$ $$=0.5\times 10^{4}$$ Since the numerical value of $a$ must be between 1 and 10, therefore $0.5\times 10^{4}$ can be written as: $$5\times 10^{3}$$
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