Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Test - Page 102: 35



Work Step by Step

$$\frac{-10x^{4}y^{3}}{-40x^{-2}y^{6}}$$ Recall the quotient rule: $\frac{a^{m}}{a^{n}}=a^{m-n}$ and $\frac{a^{n}}{a^{m}}=\frac{1}{a^{m-n}}$ Thus, $$\frac{-10x^{4}y^{3}}{-40x^{-2}y^{6}}$$ $$\frac{-10}{-40}\cdot \frac{x^{4-(-2)}}{y^{6-3}}$$ $$=\frac{x^{6}}{4y^{3}}$$
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