Answer
$$(-2x^{5})(7x^{-10})= -\frac{14}{x^{5}}$$
Work Step by Step
$$(-2x^{5})(7x^{-10})$$
Recall the product rule: $a^{m}⋅a^{n}=a^{m+n}$
Thus,
$$(-2x^{5})(7x^{-10})$$ $$=(-2)(7)(x^{5+(-10)})$$ $$=-14x^{-5}$$
Recall the negative exponent rule: $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}} = a^{n}$
Thus,
$$-14x^{-5} = -\frac{14}{x^{5}}$$
