Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 82: 167

Answer

a. $10^{5} = 1000000$ b. $10^{6} = 10000000$

Work Step by Step

a. $10^{9}$ x $10^{-4}$ Recall the product rule: $a^{m}⋅a^{n}=a^{m+n}$ Hence, $$10^{9} \cdot 10^{-4} = 10^{9+(-4)}$$ $$=10^{5}$$ To evaluate the expression, move the decimal point $5$ places to the right since the exponent is positive. Thus, $$10^{5} = 1000000$$ b. $\frac{10^{4}}{10^{-2}}$ Recall the quotient rule: $\frac{a^{m}}{a^{n}}=a^{m-n}$ and $\frac{a^{n}}{a^{m}}=\frac{1}{a^{m+n}}$ if $m>n$ Hence, $$\frac{10^{4}}{10^{-2}} = \frac{10^{4}}{10^{-2}}$$ $$=10^{4-(-2)}$$ $$=10^{6}$$ To evaluate the expression, move the decimal point $6$ places to the right since the exponent is positive. Thus, $$10^{6} = 10000000$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.