Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 82: 158


$$x^{(n-1)} \cdot x^{(3n+4)}=x^{4n+3}$$

Work Step by Step

$$x^{(n-1)} \cdot x^{(3n+4)}$$ Recall the product rule: $a^{m}⋅a^{n}=a^{m+n}$ Thus, $$x^{(n-1)} \cdot x^{(3n+4)}$$ $$x^{(n-1)+(3n+4)}$$ Remove the parentheses in the exponents: $$x^{(n-1)+(3n+4)}$$ $$=x^{4n+3}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.