Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 82: 164

Answer

width = 40 meters length = 75 meters

Work Step by Step

Let $x$ be the width of the field. Hence, Width = $x$ Length = $2x-5$ Since the field is enclosed by a $230$-meter fence. Then this means that $230$ meters is the perimeter of the field. The formula for the perimeter of a rectangle is given by the equation: $P = 2L + 2W$ Substitute the expressions for length and width, as well as the value of the perimeter: $$230 = 2(2x-5) + 2x$$ Evaluate the equation. $$230 = 2(2x-5) + 2x$$ $$230= 4x - 10 + 2x$$ $$230 = 6x - 10$$ Add $10$ to both sides: $$230 + 10 = 6x - 10 + 10$$ $$240 = 6x$$ Divide both sides by $6$: $$\frac{230}{6} = \frac{6x}{6}$$ $$40 = x$$ Thus, width = $40$ meters length = $2x-5$ $=2(40)-5$ $=75$ meters
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