## Intermediate Algebra for College Students (7th Edition)

$x=-8$
$\frac{2x}{3}-\frac{8}{3}=x$ Add $\frac{8}{3}$ on both sides. $\frac{2x}{3}-\frac{8}{3}+\frac{8}{3}=x+\frac{8}{3}$ $\frac{2x}{3}=x+\frac{8}{3}$ Multiply both sides by $3$. $\frac{2x}{3}(3)=(x+\frac{8}{3})(3)$ $2x=3x+8$ Subtract $3x$ from both sides. $2x-3x=3x-3x+8$ $-x=8$ $x=-8$