Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 69: 98



Work Step by Step

$\frac{2x}{3}-\frac{8}{3}=x$ Add $\frac{8}{3}$ on both sides. $\frac{2x}{3}-\frac{8}{3}+\frac{8}{3}=x+\frac{8}{3}$ $\frac{2x}{3}=x+\frac{8}{3}$ Multiply both sides by $3$. $\frac{2x}{3}(3)=(x+\frac{8}{3})(3)$ $2x=3x+8$ Subtract $3x$ from both sides. $2x-3x=3x-3x+8$ $-x=8$ $x=-8$
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