Answer
$10$ correct solved examples and $16$ incorrect solved example.
Work Step by Step
Let $a$ be the correct solved problem and $b$ be the incorrect.
Total number of questions = 26
Thus,
$a+b=26$
and $ a$ correct solved problems = 8 cent ; $b$ incorrect solved problems = 5 cent
Thus, $8a=5b$
Now, $a=\dfrac{5b}{8}$
Now, form equation $a+b=26$, we have
$\dfrac{5b}{8}+b=26$
or, $b=16$
and $a= 26-b=26-16=10$
Hence, $10$ correct solved examples and $16$ incorrect solved example.
