Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 69: 94

Answer

Originally stolen $=36$ plants.

Work Step by Step

Let the number of stolen plants $=x$. The thief is forced to give $\frac{1}{2}$ of stolen plant $+2$. For the first thief: He gave $\frac{x}{2}+2$. Remaining number of plants. $=x-(\frac{x}{2}+2)$ Simplify. $=x-\frac{x}{2}-2$ $=\frac{x}{2}-2$ For the second thief: He gave $=\frac{1}{2}(\frac{x}{2}-2)+2$. Simplify. $=\frac{x}{4}-1+2$ $=\frac{x}{4}+1$ Remaining number of plants. $=\frac{x}{2}-2-(\frac{x}{4}+1)$ $=\frac{x}{2}-2-\frac{x}{4}-1$ Simplify. $=\frac{x}{4}-3$ For the third thief: He gave $=\frac{1}{2}(\frac{x}{4}-3)+2$. Simplify. $=\frac{x}{8}-\frac{3}{2}+2$ $=\frac{x}{8}+\frac{1}{2}$ Remaining number of plants. $=\frac{x}{4}-3-(\frac{x}{8}+\frac{1}{2})$ Simplify. $=\frac{x}{4}-3-\frac{x}{8}-\frac{1}{2}$ $=\frac{x}{8}-\frac{7}{2}$ After the third thief remaining number of plants $=1$. $\Rightarrow \frac{x}{8}-\frac{7}{2}=1$ Add $\frac{7}{2}$ both sides. $\Rightarrow \frac{x}{8}-\frac{7}{2}+\frac{7}{2}=1+\frac{7}{2}$ Simplify. $\Rightarrow \frac{x}{8}=\frac{9}{2}$ Multiply by $8$ on both sides. $\Rightarrow 8\cdot \frac{x}{8}=8\cdot \frac{9}{2}$ Simplify. $\Rightarrow x=36$.
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