Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.5 Series - 9.5 Exercises - Page 747: 40

Answer

$1,953,120$

Work Step by Step

$\dfrac{a_{n+1}}{a_n}=\dfrac{4(5^{n+1})}{4(5^n)}=5$ Since the ratio between consecutive terms is constant, the given sequence is geometric. The first term is $a_1=4(5^1)=20$. The common ratio is $r=5$. The formula for the sum of the first $n$ terms is: $S_{n}=\frac{a_{1}(1-r^{n})}{1-r}$ $S_{8}=\frac{20(1-5^{8})}{1-5}=1,953,120$
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