Answer
$3+9+27+81=120$
Work Step by Step
We have to sum the first four terms of the sequence whose general term is $a_{n}=3^{n}$. This yields
$\sum\limits^{4}_{n=1}(3^{n})=3^{1}+3^{2}+3^{3}+3^{4}$
$=3+9+27+81=120$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 9 - Conic Sections, Sequences, and Series - 9.5 Series - 9.5 Exercises - Page 746: 6
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