Answer
$4+16+64+256=340$
Work Step by Step
We have to sum the first four terms of the sequence whose general term is $a_{n}=4^{n}$. This yields
$\sum\limits^{4}_{n=1}(4^{n})=4^{1}+4^{2}+4^{3}+4^{4}$
$=4+16+64+256=340$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 9 - Conic Sections, Sequences, and Series - 9.5 Series - 9.5 Exercises - Page 746: 5
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