Answer
$\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+\frac{1}{8}+\frac{1}{10}=\frac{137}{120}$.
Work Step by Step
We need to sum the first five terms of the sequence whose general term is $a_{n}=\frac{1}{2n}$. This yields
$\sum\limits^{5}_{n=1}(\frac{1}{2n})=\frac{1}{2(1)}+\frac{1}{2(2)}+\frac{1}{2(3)}+\frac{1}{2(4)}+\frac{1}{2(5)}$
$=\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+\frac{1}{8}+\frac{1}{10}$
$=\frac{60}{120}+\frac{30}{120}+\frac{20}{120}+\frac{15}{120}+\frac{12}{120}$
$=\frac{137}{120}$
