Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.4 Solving Radical Equations - 8.4 Exercises - Page 655: 90

Answer

$d= -8$

Work Step by Step

Given \begin{equation} \sqrt[3]{7 d-8}=-4. \end{equation} This is a radical equation. The solution steps are shown below. \begin{equation} \begin{aligned} \sqrt[3]{7 d-8}&=-4\\ \left( \sqrt[3]{7 d-8} \right)^3 & = \left(-4 \right)^3\\ 7 d-8&=-64\\ d&= \frac{-64+8}{7}\\ &= -8. \end{aligned} \end{equation} Check. \begin{equation} \begin{aligned} \sqrt[3]{7 (-8)-8}&\stackrel{?}{=} 3\\ -4& =-4\quad \quad \textbf{True} \end{aligned} \end{equation} The solution is $d= -8 $.
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