Answer
$g= -\frac{20}{3}$
Work Step by Step
Given \begin{equation}
6 g+8=3(g-4).
\end{equation}
The is linear equation in the variable $g$. We solve it:
\begin{equation}
\begin{aligned}
6 g+8&=3(g-4)\\\
6 g+8 & =3g-12\\
6g-3g& =-12-8 \\
g& =-\frac{20}{3}.
\end{aligned}
\end{equation} The solution is $g= -\frac{20}{3}$.
