Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.4 Solving Radical Equations - 8.4 Exercises - Page 652: 4

Answer

$x = 24$ To check if our solution is correct, we plug it into the original equation: $\sqrt {7(24) + 1} = 13$ Multiply to simplify: $\sqrt {168 + 1} = 13$ Evaluate what is inside the radical: $\sqrt {169} = 13$ Evaluate the square root: $13 = 13$

Work Step by Step

We need to get rid of the radical, so we square both sides of the equation: $7x + 1 = 13^{2}$ Evaluate the right side of the equation: $7x + 1 = 169$ Subtract $1$ from both sides of the equation to collect constants on the right side of the equation: $7x = 168$ Divide both sides by $7$ to solve for $x$: $x = 24$ To check if our solution is correct, we plug it into the original equation: $\sqrt {7(24) + 1} = 13$ Multiply to simplify: $\sqrt {168 + 1} = 13$ Evaluate what is inside the radical: $\sqrt {169} = 13$ Evaluate the square root: $13 = 13$
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