Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.4 Solving Radical Equations - 8.4 Exercises - Page 652: 12

Answer

$20.83$ feet

Work Step by Step

Given $$s=\sqrt{30 f d},\tag{1}$$ where $s$ is the speed of the car in mile per hour, $f$ is the coefficient of friction on the road and $d$ is the length of the skid mark on the road. Given that $s= 25$ mph and $f= 1$, we can find $d$ by solving equation $(1)$: \begin{equation} \begin{aligned} s^2 & =\left( \sqrt{30\cdot 1\cdot d} \right)^2 \\ s^2& = 30d \\ \frac{s^2}{30}& =d\\ \frac{625}{30}&= d\\ d&= \frac{125}{6}\approx 20.83. \end{aligned} \end{equation}
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