Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises: 26

Answer

$32+8\sqrt {14}-12\sqrt 2-6\sqrt 7$

Work Step by Step

$(8-\sqrt {18})(4+\sqrt {14})$ =$8(4+\sqrt {14})-\sqrt {18}(4+\sqrt {14})$ =$32+8\sqrt {14}-4\sqrt {18}-(\sqrt {14}\sqrt {18})$ =$32+8\sqrt {14}-4\sqrt {2\times9}-\sqrt {14\times18}$ =$32+8\sqrt {14}-4\sqrt 9\sqrt 2-\sqrt {252}$ =$32+8\sqrt {14}-4(3)\sqrt 2-\sqrt {36\times7}$ =$32+8\sqrt {14}-12\sqrt 2-(\sqrt {36}\times\sqrt 7)$ =$32+8\sqrt {14}-12\sqrt 2-6\sqrt 7$
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