#### Answer

$6b$

#### Work Step by Step

Step 1: $\sqrt[3] {24b^{2}}\times\sqrt[3] {9b}$
Step 2: $\sqrt[3] {24b^{2}\times9b}$
Step 3: $\sqrt[3] {216b^{3}}$
Step 4:$\sqrt[3] {216}\times\sqrt[3] {b^{3}}$
Step 5: $6\times b$
Step 6: $6b$

Published by
Brooks Cole

ISBN 10:
0-53449-636-9

ISBN 13:
978-0-53449-636-4

$6b$

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