Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises - Page 642: 23

Answer

$12+4\sqrt 2+3\sqrt 5+\sqrt {10}$

Work Step by Step

$(4+\sqrt 5)(3+\sqrt 2)$ =$4(3+\sqrt 2)+\sqrt 5(3+\sqrt 2)$ =$12+4\sqrt 2+3\sqrt 5+(\sqrt 2\sqrt 5)$ =$12+4\sqrt 2+3\sqrt 5+\sqrt {2\times5}$ =$12+4\sqrt 2+3\sqrt 5+\sqrt {10}$
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