Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.5 Solving Rational Equations - 7.5 Exercises - Page 598: 1



Work Step by Step

Multiply $x+2$ to both sides of the equation to obtain: $6(x+2) = \dfrac{30}{x+2} \cdot (x+2) \\6(x)+6(2)=30 \\6x+12=30$ Subtract $12$ to both sides of the equation to obtain: $6x=30-12 \\6x=18$ Divide $6$ to both sides to obtain: $x = 3$ Cheking: $6=\dfrac{30}{3+2}? \\6 = \dfrac{30}{5}? \\6=6$ Thus, the solution to the given equation is: $3$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.