Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.1 Rational Functions and Variation - 7.1 Exercises - Page 565: 19

Answer

a) $y= \frac{10935}{x^3}$ b) $y= 87.48$

Work Step by Step

Since $y$ varies inversely with $x^3$, we can write \begin{equation} y= \frac{k}{x^3}, \end{equation} where $k$ is the constant of proportionality that must be determined. a) Given that $y= 405$ when $x= 3$, we can use this information to find $k$ as follows: \begin{equation} \begin{aligned} 405&= \frac{k}{3^3}\\ 405\cdot 27&=k\\ \therefore k&=10935. \end{aligned} \end{equation} The required equation is \begin{equation} y= \frac{10935}{x^3}. \end{equation} b) Determine $y$ when $x=5$. \begin{equation} y= \frac{10935}{5^3}= 87.48. \end{equation} The answer is $y= 87.48$ when $x= 5$.
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