Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - Chapter Review Exercises - Page 542: 40

Answer

$x=-2$

Work Step by Step

$4\left(\frac{1}{3}\right)^x-8=28$ $4\left(\frac{1}{3}\right)^x=28+8$ $4\left(\frac{1}{3}\right)^x=36$ $\left(\frac{1}{3}\right)^x=\frac{36}{4}$ $(\frac{1}{3})^x=9$ $\left(\frac{1}{3}\right)^x=3^2$ $(3^{-1})^{x}=3^2$ $3^{-x}=3^2$ $-x=2 $ $x=-2$
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