Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - Chapter Review Exercises: 15

Answer

$= -3$

Work Step by Step

$\log_2 (\frac{1}{8})$ $= \log_2 8^{-1}$ $= \log_2 2^{-3}$ $= -3$
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