Intermediate Algebra: Connecting Concepts through Application

$x\approx1.841$
Isolate the exponential term on one side. Then take the log of both sides, and then use the power property. $17(1.9)^x=55.4$ $1.9^x=\frac{55.4}{17}$ $x\log1.9=\log\frac{55.4}{17}$ $x=\frac{\log\frac{55.4}{17}}{\log1.9}$ $x\approx1.841$