## Intermediate Algebra: Connecting Concepts through Application

$f^{-1}(x) = \log_{12} x$
$f(x) = 12^{x}$ Let $f(x) = y$ $y = 12^{x}$ Swap the $x$ and $y$ variable to find the inverse: $x = 12^{y}$ $y = \log_{12} x$ $f^{-1}(x) = \log_{12} x$