Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.2 Logarithmic Functions - 6.2 Exercises: 53

Answer

$\approx 4.227$

Work Step by Step

The base of the logarithm is not $10$, therefore you require the change of base formula before evaluating: $= \log_{12} (36478)$ $= \frac{\log 36478}{\log 12}$ $= 4.22730...$ $\approx 4.227$
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